What is the general solution for cos(-(pi/6)-2x)=1 ?

The general solution for cos(-(pi/6)-2x)=1 is x=-pin-pi/(12)

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cos(-(pi/6)-2x)=1

cos (- (\frac{π}{6}) - 2 x) = 1

x = - πn - \frac{π}{12}

Solution steps

cos (- (\frac{π}{6}) - 2 x) = 1

General solutions for

cos (- \frac{π}{6} - 2 x) = 1

- \frac{π}{6} - 2 x = 0 + 2 πn

Solve

- \frac{π}{6} - 2 x = 0 + 2 πn : x = - πn - \frac{π}{12}

x = - πn - \frac{π}{12}

2 sin (θ) cos (θ) + 2 cos (θ) = 0

3 tan (2 x) = 5

3 - 2 cos (θ) = 3 - 2 sin (θ)

(4 cos (x) - 2 sin (x))^{2} + 12 sin^{2} (x) = 16

arcsin (x) = π

What is the general solution for cos(-(pi/6)-2x)=1 ?
The general solution for cos(-(pi/6)-2x)=1 is x=-pin-pi/(12)