What is the general solution for 1-cos(x)=cos(x) ?

The general solution for 1-cos(x)=cos(x) is x= pi/3+2pin,x=(5pi)/3+2pin

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1-cos(x)=cos(x)

1 - cos (x) = cos (x)

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

1 - cos (x) = cos (x)

Solve by substitution

cos (x) = \frac{1}{2}

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

2 cos^{3} (θ) = cos (θ)

t, x = arccos (\frac{1}{1 + t ^{2}})

sin (x) \cdot cos (x) = sin (2 x)

(1 - sin (x)) (1 + cos (x)) = cos^{2} (x)

What is the general solution for 1-cos(x)=cos(x) ?
The general solution for 1-cos(x)=cos(x) is x= pi/3+2pin,x=(5pi)/3+2pin