What is the general solution for 4sec(θ)-sqrt(3)=sqrt(3)+7sec(θ) ?

The general solution for 4sec(θ)-sqrt(3)=sqrt(3)+7sec(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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4sec(θ)-sqrt(3)=sqrt(3)+7sec(θ)

4 sec (θ) - 3 = 3 + 7 sec (θ)

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

4 sec (θ) - 3 = 3 + 7 sec (θ)

Solve by substitution

sec (θ) = - \frac{2 3}{3}

sec (θ) = - \frac{2 3}{3} : θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Combine all the solutions

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

\frac{1}{15} = cos (x)

cos^{2} (θ) = 3 sin^{2} (θ)

sinh (x) = \frac{5}{4}

3 - 4 cos (A) = 1

3 tan (x) - 2 cos (x) = 0

What is the general solution for 4sec(θ)-sqrt(3)=sqrt(3)+7sec(θ) ?
The general solution for 4sec(θ)-sqrt(3)=sqrt(3)+7sec(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin