What is the general solution for 4cos(2x)+1=3 ?

The general solution for 4cos(2x)+1=3 is x= pi/6+pin,x=(5pi)/6+pin

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4cos(2x)+1=3

4 cos (2 x) + 1 = 3

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

4 cos (2 x) + 1 = 3

Move

1

to the right side

4 cos (2 x) = 2

Divide both sides by

4

cos (2 x) = \frac{1}{2}

General solutions for

cos (2 x) = \frac{1}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{6} + πn

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

sinh^{2} (x) = 0

cos (x) csc^{2} (x) + 3 cos (x) = 7 cos (x)

sin (x) - cos (x) = 1, 0 \leq x < 2 π

tan (θ) = \frac{π}{6}

\frac{1}{tan ^{2} ( x )} - cos^{2} (x) = cos^{2} (x) - cot^{2} (x)

What is the general solution for 4cos(2x)+1=3 ?
The general solution for 4cos(2x)+1=3 is x= pi/6+pin,x=(5pi)/6+pin