What is the general solution for sec(x+10)=5.759 ?

The general solution for sec(x+10)=5.759 is x=1.39627…+360n-10,x=360-1.39627…+360n-10

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sec(x+10)=5.759

sec (x + 1 0^{\circ}) = 5.759

x = 1.39627 \dots + 36 0^{\circ} n - 1 0^{\circ}, x = 36 0^{\circ} - 1.39627 \dots + 36 0^{\circ} n - 1 0^{\circ}

Solution steps

sec (x + 1 0^{\circ}) = 5.759

Apply trig inverse properties

x + 1 0^{\circ} = arcsec (5.759) + 36 0^{\circ} n, x + 1 0^{\circ} = 36 0^{\circ} - arcsec (5.759) + 36 0^{\circ} n

Solve

x + 1 0^{\circ} = arcsec (5.759) + 36 0^{\circ} n : x = arcsec (5.759) + 36 0^{\circ} n - 1 0^{\circ}

Solve

x + 1 0^{\circ} = 36 0^{\circ} - arcsec (5.759) + 36 0^{\circ} n : x = 36 0^{\circ} - arcsec (5.759) + 36 0^{\circ} n - 1 0^{\circ}

x = arcsec (5.759) + 36 0^{\circ} n - 1 0^{\circ}, x = 36 0^{\circ} - arcsec (5.759) + 36 0^{\circ} n - 1 0^{\circ}

Show solutions in decimal form

x = 1.39627 \dots + 36 0^{\circ} n - 1 0^{\circ}, x = 36 0^{\circ} - 1.39627 \dots + 36 0^{\circ} n - 1 0^{\circ}

cos (3 x + \frac{π}{4}) = \frac{3}{2}

- sin (4 x) = sin (8 x)

tan (θ) = \frac{3 3}{3}

cos (2 x) = 1 - sin^{2} (2 x), 0 \leq x \leq 2 π

2 = sec (x) tan (x)

What is the general solution for sec(x+10)=5.759 ?
The general solution for sec(x+10)=5.759 is x=1.39627…+360n-10,x=360-1.39627…+360n-10