What is the general solution for 2sec^2(θ)+3=4+sec^2(θ) ?

The general solution for 2sec^2(θ)+3=4+sec^2(θ) is θ=2pin,θ=pi+2pin

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2sec^2(θ)+3=4+sec^2(θ)

2 sec^{2} (θ) + 3 = 4 + sec^{2} (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

2 sec^{2} (θ) + 3 = 4 + sec^{2} (θ)

Solve by substitution

sec (θ) = 1, sec (θ) = - 1

sec (θ) = 1 : θ = 2 πn

sec (θ) = - 1 : θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

3 cos^{2} (x) - 5 cos (x) - 2 = 0

cos (2 x) + 1 = - 2 cos (x)

sin (θ) = \frac{- 1}{2}, 0 \leq θ \leq 4 π

4 cos^{2} (x) + 2 cos (x) = 2, 0 \leq x \leq 2 π

arctan (x) + arctan (2 x) = \frac{π}{4}

What is the general solution for 2sec^2(θ)+3=4+sec^2(θ) ?
The general solution for 2sec^2(θ)+3=4+sec^2(θ) is θ=2pin,θ=pi+2pin