What is the general solution for 1+cos(θ)=(2+sqrt(3))/2 ?

The general solution for 1+cos(θ)=(2+sqrt(3))/2 is θ=0.52359…+2pin,θ=2pi-0.52359…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1+cos(θ)=(2+sqrt(3))/2

1 + cos (θ) = \frac{2 + 3}{2}

θ = 0.52359 \dots + 2 πn, θ = 2 π - 0.52359 \dots + 2 πn

Solution steps

1 + cos (θ) = \frac{2 + 3}{2}

Move

1

to the right side

cos (θ) = \frac{2 + 3}{2} - 1

Apply trig inverse properties

θ = arccos (\frac{2 + 3}{2} - 1) + 2 πn, θ = 2 π - arccos (\frac{2 + 3}{2} - 1) + 2 πn

Show solutions in decimal form

θ = 0.52359 \dots + 2 πn, θ = 2 π - 0.52359 \dots + 2 πn

1 + 3 sin (x) = 2

cos (\frac{x}{2} + \frac{π}{3}) = \frac{1}{2}

sinh (x) = \frac{2}{2}

sin^{2} (2 x) = cos^{2} (x)

- 2 sin (2 x) sin (x) = sin (2 x)

What is the general solution for 1+cos(θ)=(2+sqrt(3))/2 ?
The general solution for 1+cos(θ)=(2+sqrt(3))/2 is θ=0.52359…+2pin,θ=2pi-0.52359…+2pin