What is the general solution for 2sin(6x)-1=0 ?

The general solution for 2sin(6x)-1=0 is x= pi/(36)+(pin)/3 ,x=(5pi}{36}+\frac{pin)/3

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2sin(6x)-1=0

2 sin (6 x) - 1 = 0

x = \frac{π}{36} + \frac{πn}{3}, x = \frac{5 π}{36} + \frac{πn}{3}

Solution steps

2 sin (6 x) - 1 = 0

Move

1

to the right side

2 sin (6 x) = 1

Divide both sides by

2

sin (6 x) = \frac{1}{2}

General solutions for

sin (6 x) = \frac{1}{2}

6 x = \frac{π}{6} + 2 πn, 6 x = \frac{5 π}{6} + 2 πn

Solve

6 x = \frac{π}{6} + 2 πn : x = \frac{π}{36} + \frac{πn}{3}

Solve

6 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{36} + \frac{πn}{3}

x = \frac{π}{36} + \frac{πn}{3}, x = \frac{5 π}{36} + \frac{πn}{3}

sin^{2} (x) = \frac{( 6 m - 5 )}{5}

sin^{2} (θ) - sin (θ) - 6 = 0

cos (2 θ) - 3 cos (θ) + 2 = 0

u, x = 2 tanh (u)

4 cos^{2} (x) + cos (2 x) - 7 cos (x) = - 2

What is the general solution for 2sin(6x)-1=0 ?
The general solution for 2sin(6x)-1=0 is x= pi/(36)+(pin)/3 ,x=(5pi}{36}+\frac{pin)/3