What is the general solution for 6sin(x)+1=0 ?

The general solution for 6sin(x)+1=0 is x=-0.16744…+2pin,x=pi+0.16744…+2pin

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6sin(x)+1=0

6 sin (x) + 1 = 0

x = - 0.16744 \dots + 2 πn, x = π + 0.16744 \dots + 2 πn

Degrees

x = - 9.59406 \dots^{\circ} + 36 0^{\circ} n, x = 189.59406 \dots^{\circ} + 36 0^{\circ} n

Solution steps

6 sin (x) + 1 = 0

Move

1

to the right side

6 sin (x) + 1 = 0

Subtract

1

from both sides

6 sin (x) + 1 - 1 = 0 - 1

Simplify

6 sin (x) = - 1

6 sin (x) = - 1

Divide both sides by

6

6 sin (x) = - 1

Divide both sides by

6

\frac{6 sin ( x )}{6} = \frac{- 1}{6}

Simplify

sin (x) = - \frac{1}{6}

sin (x) = - \frac{1}{6}

Apply trig inverse properties

sin (x) = - \frac{1}{6}

General solutions for

sin (x) = - \frac{1}{6}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{1}{6}) + 2 πn, x = π + arcsin (\frac{1}{6}) + 2 πn

x = arcsin (- \frac{1}{6}) + 2 πn, x = π + arcsin (\frac{1}{6}) + 2 πn

Show solutions in decimal form

x = - 0.16744 \dots + 2 πn, x = π + 0.16744 \dots + 2 πn

π + 3 arccos (x + 1) = 0

5 sin (2 x) + 3 cos (2 x) = 0

x, sin (2 x) - sin (x) = 0

x, sin (x^{e}) + cos (y^{e}) = 1

sin^{2} (x) + 3 cos (x) - 1 = 2

What is the general solution for 6sin(x)+1=0 ?
The general solution for 6sin(x)+1=0 is x=-0.16744…+2pin,x=pi+0.16744…+2pin