What is the general solution for sin^2(x)+cos(2x)=0 ?

The general solution for sin^2(x)+cos(2x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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sin^2(x)+cos(2x)=0

sin^{2} (x) + cos (2 x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) + cos (2 x) = 0

Rewrite using trig identities

cos^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (x) = 0

General solutions for

cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

42 cos (x) - 8 sin (x) cos (x) = 0

sin (x) = cos (x + \frac{π}{2})

cos (θ) = \frac{2}{3}, - \frac{5 π}{2}, 2 π

6 cos (2 x) = 32

2 cos^{2} (x) - sin^{2} (x) = 0

What is the general solution for sin^2(x)+cos(2x)=0 ?
The general solution for sin^2(x)+cos(2x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin