What is the general solution for 10cos(x)+4=10 ?

The general solution for 10cos(x)+4=10 is x=0.92729…+2pin,x=2pi-0.92729…+2pin

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10cos(x)+4=10

10 cos (x) + 4 = 10

x = 0.92729 \dots + 2 πn, x = 2 π - 0.92729 \dots + 2 πn

Degrees

x = 53.13010 \dots^{\circ} + 36 0^{\circ} n, x = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Solution steps

10 cos (x) + 4 = 10

Move

4

to the right side

10 cos (x) + 4 = 10

Subtract

4

from both sides

10 cos (x) + 4 - 4 = 10 - 4

Simplify

10 cos (x) = 6

10 cos (x) = 6

Divide both sides by

10

10 cos (x) = 6

Divide both sides by

10

\frac{10 cos ( x )}{10} = \frac{6}{10}

Simplify

cos (x) = \frac{3}{5}

cos (x) = \frac{3}{5}

Apply trig inverse properties

cos (x) = \frac{3}{5}

General solutions for

cos (x) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{3}{5}) + 2 πn, x = 2 π - arccos (\frac{3}{5}) + 2 πn

x = arccos (\frac{3}{5}) + 2 πn, x = 2 π - arccos (\frac{3}{5}) + 2 πn

Show solutions in decimal form

x = 0.92729 \dots + 2 πn, x = 2 π - 0.92729 \dots + 2 πn

x, arctan (x) = \frac{π}{4}

cos (2 θ) + 3 cos (θ) = 1

coth (x) = 1

sin (3 x) + sin (x) = cos (x)

sin^{2} (θ) - 2 = sin (θ), - π \leq x \leq 2 π

What is the general solution for 10cos(x)+4=10 ?
The general solution for 10cos(x)+4=10 is x=0.92729…+2pin,x=2pi-0.92729…+2pin