What is the general solution for 2sin(pi/3-x)=1 ?

The general solution for 2sin(pi/3-x)=1 is x=-2pin+pi/6 ,x=-2pin-pi/2

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2sin(pi/3-x)=1

2 sin (\frac{π}{3} - x) = 1

x = - 2 πn + \frac{π}{6}, x = - 2 πn - \frac{π}{2}

Solution steps

2 sin (\frac{π}{3} - x) = 1

Divide both sides by

2

sin (\frac{π}{3} - x) = \frac{1}{2}

General solutions for

sin (\frac{π}{3} - x) = \frac{1}{2}

\frac{π}{3} - x = \frac{π}{6} + 2 πn, \frac{π}{3} - x = \frac{5 π}{6} + 2 πn

Solve

\frac{π}{3} - x = \frac{π}{6} + 2 πn : x = - 2 πn + \frac{π}{6}

Solve

\frac{π}{3} - x = \frac{5 π}{6} + 2 πn : x = - 2 πn - \frac{π}{2}

x = - 2 πn + \frac{π}{6}, x = - 2 πn - \frac{π}{2}

9 tan^{2} (z) cos (z) = 3 cos (z)

sin (2 x) sin (4 x) = cos (2 x) cos (4 x)

\frac{1}{sec ( θ )} = - \frac{7}{25}

3 tan^{3} (x) - 2 tan^{2} (x) - 32 tan (x) - 32 = 0

x, 2 sin (5 x) - 1 = 0

What is the general solution for 2sin(pi/3-x)=1 ?
The general solution for 2sin(pi/3-x)=1 is x=-2pin+pi/6 ,x=-2pin-pi/2