What is the general solution for 2sin((pix)/2)+1=0 ?

The general solution for 2sin((pix)/2)+1=0 is x= 7/3+4n,x= 11/3+4n

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2sin((pix)/2)+1=0

2 sin (\frac{π x}{2}) + 1 = 0

x = \frac{7}{3} + 4 n, x = \frac{11}{3} + 4 n

Solution steps

2 sin (\frac{π x}{2}) + 1 = 0

Move

1

to the right side

2 sin (\frac{π x}{2}) = - 1

Divide both sides by

2

sin (\frac{π x}{2}) = - \frac{1}{2}

General solutions for

sin (\frac{π x}{2}) = - \frac{1}{2}

\frac{π x}{2} = \frac{7 π}{6} + 2 πn, \frac{π x}{2} = \frac{11 π}{6} + 2 πn

Solve

\frac{π x}{2} = \frac{7 π}{6} + 2 πn : x = \frac{7}{3} + 4 n

Solve

\frac{π x}{2} = \frac{11 π}{6} + 2 πn : x = \frac{11}{3} + 4 n

x = \frac{7}{3} + 4 n, x = \frac{11}{3} + 4 n

sin (x) = 0.819

tan (x) = 1.1

sin (x) = 45

sin (x) = 90

cos (x) = - \frac{4}{5}, sin (x)

What is the general solution for 2sin((pix)/2)+1=0 ?
The general solution for 2sin((pix)/2)+1=0 is x= 7/3+4n,x= 11/3+4n