What is the general solution for sin^2(θ)-2=sin(θ) ?

The general solution for sin^2(θ)-2=sin(θ) is θ=(3pi)/2+2pin

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sin^2(θ)-2=sin(θ)

sin^{2} (θ) - 2 = sin (θ)

θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) - 2 = sin (θ)

Solve by substitution

sin (θ) = 2, sin (θ) = - 1

sin (θ) = 2 :

No Solution

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

5 + 4 cos (x) = 0

csc^{2} (x) - csc (x) - 2 = 0, 0 \leq x \leq 2 π

sinh (x - 1) = 0

32 cos (x) - 6 sin (x) cos (x) = 0

tan (θ) = - \frac{6}{3}

What is the general solution for sin^2(θ)-2=sin(θ) ?
The general solution for sin^2(θ)-2=sin(θ) is θ=(3pi)/2+2pin