What is the general solution for 4cos(A)+3=2cos(A)+4 ?

The general solution for 4cos(A)+3=2cos(A)+4 is A= pi/3+2pin,A=(5pi)/3+2pin

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4cos(A)+3=2cos(A)+4

4 cos (A) + 3 = 2 cos (A) + 4

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

Solution steps

4 cos (A) + 3 = 2 cos (A) + 4

Solve by substitution

cos (A) = \frac{1}{2}

cos (A) = \frac{1}{2} : A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

Combine all the solutions

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

sin^{2} (x) - tan (x) = 0

6 sin^{3} (x) + 7 sin^{2} (x) - sin (x) - 2 = 0

2 sin (x) cos^{2} (x) - sin (x) = 0

tan (x) = \frac{1}{sec ( x )}

2 \cdot cos (2 x) - 1 = 0

What is the general solution for 4cos(A)+3=2cos(A)+4 ?
The general solution for 4cos(A)+3=2cos(A)+4 is A= pi/3+2pin,A=(5pi)/3+2pin