What is the general solution for 2sec(x)+4=0 ?

The general solution for 2sec(x)+4=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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2sec(x)+4=0

2 sec (x) + 4 = 0

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

2 sec (x) + 4 = 0

Move

4

to the right side

2 sec (x) = - 4

Divide both sides by

2

sec (x) = - 2

General solutions for

sec (x) = - 2

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

2 sec^{2} (x) - 5 sec (x) + 2 = 0

sin (\frac{1}{3} x + \frac{3 π}{2}) = 0

2 cos (x) = 3 sin (x)

4 sin^{2} (θ) - 8 cos (θ) + 1 = 0

sin (x) cos (\frac{π}{7}) - sin (\frac{π}{7}) cos (x) = \frac{2}{2}

What is the general solution for 2sec(x)+4=0 ?
The general solution for 2sec(x)+4=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin