What is the general solution for -5cos(c)-1=2cos(c)+3 ?

The general solution for -5cos(c)-1=2cos(c)+3 is c=2.17904…+2pin,c=-2.17904…+2pin

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-5cos(c)-1=2cos(c)+3

- 5 cos (c) - 1 = 2 cos (c) + 3

c = 2.17904 \dots + 2 πn, c = - 2.17904 \dots + 2 πn

Solution steps

- 5 cos (c) - 1 = 2 cos (c) + 3

Solve by substitution

cos (c) = - \frac{4}{7}

cos (c) = - \frac{4}{7} : c = arccos (- \frac{4}{7}) + 2 πn, c = - arccos (- \frac{4}{7}) + 2 πn

Combine all the solutions

c = arccos (- \frac{4}{7}) + 2 πn, c = - arccos (- \frac{4}{7}) + 2 πn

Show solutions in decimal form

c = 2.17904 \dots + 2 πn, c = - 2.17904 \dots + 2 πn

3 tan (t) - cot (t) - 5 = 0

tan^{2} (x) - 5 tan (x) - 9 = 0

arctan (t) = \frac{π}{4}

tan (\frac{π}{2} - θ) = cos (- θ)

tan (x) = - \frac{24}{7}

What is the general solution for -5cos(c)-1=2cos(c)+3 ?
The general solution for -5cos(c)-1=2cos(c)+3 is c=2.17904…+2pin,c=-2.17904…+2pin