What is the general solution for sin(θ)=(60sin(15))/(400) ?

The general solution for sin(θ)=(60sin(15))/(400) is θ=0.03883…+360n,θ=180-0.03883…+360n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=(60sin(15))/(400)

sin (θ) = \frac{60 sin ( 1 5 ^{\circ} )}{400}

θ = 0.03883 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.03883 \dots + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{60 sin ( 1 5 ^{\circ} )}{400}

sin (1 5^{\circ}) = \frac{6 - 2}{4}

sin (θ) = \frac{60 \cdot \frac{6 - 2}{4}}{400}

Simplify

\frac{60 \cdot \frac{6 - 2}{4}}{400} : \frac{3 ( 6 - 2 )}{80}

Apply trig inverse properties

θ = arcsin (\frac{3 ( 6 - 2 )}{80}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{3 ( 6 - 2 )}{80}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.03883 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.03883 \dots + 36 0^{\circ} n

sin^{2} (x) - 3 cos (x) - 1 = 0

2 cos^{2} (θ) + 2 cos (θ) = 0

3 sin^{2} (x) - sin (x) = 2

cos (2 x) + 5 sin (x) + 2 = 0, 0 \leq x \leq 2 π

2 cos (4 θ) - 1 = 0

What is the general solution for sin(θ)=(60sin(15))/(400) ?
The general solution for sin(θ)=(60sin(15))/(400) is θ=0.03883…+360n,θ=180-0.03883…+360n