What is the general solution for solvefor x,-sqrt(2)sin(x)-1=0 ?

The general solution for solvefor x,-sqrt(2)sin(x)-1=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,-sqrt(2)sin(x)-1=0

solve for

x, - 2 sin (x) - 1 = 0

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

- 2 sin (x) - 1 = 0

Move

1

to the right side

- 2 sin (x) = 1

Divide both sides by

- 2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sin (t) = \frac{1}{8}

sin (θ) - 0.2 \cdot cos (θ) = 0.48979

1 = 1 + 3 sin (3 θ)

cos (\frac{θ}{4}) = \frac{2}{2}

cot (x - 2) = - \frac{3}{3}

What is the general solution for solvefor x,-sqrt(2)sin(x)-1=0 ?
The general solution for solvefor x,-sqrt(2)sin(x)-1=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin