What is the general solution for cosh(x)+4sinh(x)+2=0 ?

The general solution for cosh(x)+4sinh(x)+2=0 is x=ln((-2+sqrt(19))/5)

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cosh(x)+4sinh(x)+2=0

cosh (x) + 4 sinh (x) + 2 = 0

x = ln (\frac{- 2 + 19}{5})

Solution steps

cosh (x) + 4 sinh (x) + 2 = 0

Rewrite using trig identities

\frac{e ^{x} + e ^{- x}}{2} + 4 \cdot \frac{e ^{x} - e ^{- x}}{2} + 2 = 0

\frac{e ^{x} + e ^{- x}}{2} + 4 \cdot \frac{e ^{x} - e ^{- x}}{2} + 2 = 0 : x = ln (\frac{- 2 + 19}{5})

x = ln (\frac{- 2 + 19}{5})

cos (b) = \frac{5}{13}

x, sin (x) = \frac{1}{3}

tan (A) = \frac{5}{12}

cos (\frac{x}{2}) = \frac{1 - cos ( x )}{2}

0.322 = sin (3.92232 \cdot x)

What is the general solution for cosh(x)+4sinh(x)+2=0 ?
The general solution for cosh(x)+4sinh(x)+2=0 is x=ln((-2+sqrt(19))/5)