What is the general solution for -4cos(θ)=4(1+cos(θ)) ?

The general solution for -4cos(θ)=4(1+cos(θ)) is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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-4cos(θ)=4(1+cos(θ))

- 4 cos (θ) = 4 (1 + cos (θ))

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

- 4 cos (θ) = 4 (1 + cos (θ))

Solve by substitution

cos (θ) = - \frac{1}{2}

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Combine all the solutions

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin (2 a) = 1

tan (2 x) - \frac{1}{tan ( x )} = 0

sin (x) + cos (x) + 1 = 0

tan (x) = 15

4 sin (x) = cos (x) + 2

What is the general solution for -4cos(θ)=4(1+cos(θ)) ?
The general solution for -4cos(θ)=4(1+cos(θ)) is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin