What is the general solution for arccos(x)=arcsin(1/3)+arccos(1/4) ?

The general solution for arccos(x)=arcsin(1/3)+arccos(1/4) is x=cos(0.33983…+1.31811…)

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arccos(x)=arcsin(1/3)+arccos(1/4)

arccos (x) = arcsin (\frac{1}{3}) + arccos (\frac{1}{4})

x = cos (0.33983 \dots + 1.31811 \dots)

Solution steps

arccos (x) = arcsin (\frac{1}{3}) + arccos (\frac{1}{4})

Apply trig inverse properties

arccos (x) = arcsin (\frac{1}{3}) + arccos (\frac{1}{4})

arccos (x) = a \Rightarrow x = cos (a)

x = cos (arcsin (\frac{1}{3}) + arccos (\frac{1}{4}))

x = cos (arcsin (\frac{1}{3}) + arccos (\frac{1}{4}))

Show solutions in decimal form

x = cos (0.33983 \dots + 1.31811 \dots)

sin (2 x) = cos (4 0^{\circ})

- 15 sin (x) - 8 cos (x) = 10

- 5 sec^{2} (x) + 20 = 0

1 + cos (x) = 3 \cdot sin (x)

4 sin (θ) = 2 (1 + sin (θ))

What is the general solution for arccos(x)=arcsin(1/3)+arccos(1/4) ?
The general solution for arccos(x)=arcsin(1/3)+arccos(1/4) is x=cos(0.33983…+1.31811…)