What is the general solution for 3+3cos(θ)=3+3sin(θ) ?

The general solution for 3+3cos(θ)=3+3sin(θ) is θ= pi/4+pin

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3+3cos(θ)=3+3sin(θ)

3 + 3 cos (θ) = 3 + 3 sin (θ)

θ = \frac{π}{4} + πn

Solution steps

3 + 3 cos (θ) = 3 + 3 sin (θ)

Subtract

3 + 3 sin (θ)

from both sides

3 cos (θ) - 3 sin (θ) = 0

Rewrite using trig identities

3 - 3 tan (θ) = 0

Move

3

to the right side

- 3 tan (θ) = - 3

Divide both sides by

- 3

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

sinh (x) = \frac{4}{3}

x, f^{- 1} = arctan (x^{3} - 1)

3 cos (B) + 3 = 0

sin (2 θ) = \frac{3}{4}

sin^{2} (x) = 2 \cdot sin (x) + 3

What is the general solution for 3+3cos(θ)=3+3sin(θ) ?
The general solution for 3+3cos(θ)=3+3sin(θ) is θ= pi/4+pin