What is the general solution for 9+cot^2(x)=12 ?

The general solution for 9+cot^2(x)=12 is x= pi/6+pin,x=(5pi)/6+pin

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9+cot^2(x)=12

9 + cot^{2} (x) = 12

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

9 + cot^{2} (x) = 12

Solve by substitution

cot (x) = 3, cot (x) = - 3

cot (x) = 3 : x = \frac{π}{6} + πn

cot (x) = - 3 : x = \frac{5 π}{6} + πn

Combine all the solutions

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

cos (a) = 0.8

cos (a) = 0.6

5 cos^{2} (θ) = 6 sin (θ)

8 tan (θ) = 0

12 cos^{2} (x) + 11 cos (x) - 5 = 0

What is the general solution for 9+cot^2(x)=12 ?
The general solution for 9+cot^2(x)=12 is x= pi/6+pin,x=(5pi)/6+pin