What is the general solution for cos^2(t)= 3/4 ?

The general solution for cos^2(t)= 3/4 is t= pi/6+2pin,t=(11pi)/6+2pin,t=(5pi)/6+2pin,t=(7pi)/6+2pin

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cos^2(t)= 3/4

cos^{2} (t) = \frac{3}{4}

t = \frac{π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn, t = \frac{7 π}{6} + 2 πn

Solution steps

cos^{2} (t) = \frac{3}{4}

Solve by substitution

cos (t) = \frac{3}{2}, cos (t) = - \frac{3}{2}

cos (t) = \frac{3}{2} : t = \frac{π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn

cos (t) = - \frac{3}{2} : t = \frac{5 π}{6} + 2 πn, t = \frac{7 π}{6} + 2 πn

Combine all the solutions

t = \frac{π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn, t = \frac{7 π}{6} + 2 πn

5 tan (x) - 4 = 0

4 sin (x) = - cos^{2} (x) + 1, 0 \leq x \leq 2 π

3 tan (x) sin (x) - 2 tan (x) = 0

csc^{2} (x) + 3 csc (x) - 4 = 0

2 sin (θ) = - 3, 0 \leq θ < 2 π

What is the general solution for cos^2(t)= 3/4 ?
The general solution for cos^2(t)= 3/4 is t= pi/6+2pin,t=(11pi)/6+2pin,t=(5pi)/6+2pin,t=(7pi)/6+2pin