What is the general solution for (sin(θ)-1)(sin(θ)+1)=0 ?

The general solution for (sin(θ)-1)(sin(θ)+1)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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(sin(θ)-1)(sin(θ)+1)=0

(sin (θ) - 1) (sin (θ) + 1) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

(sin (θ) - 1) (sin (θ) + 1) = 0

Solving each part separately

sin (θ) - 1 = 0 or sin (θ) + 1 = 0

sin (θ) - 1 = 0 : θ = \frac{π}{2} + 2 πn

sin (θ) + 1 = 0 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

5 sec (θ) - 6 = 0

sec (x) = - 1, - 2 π \leq x \leq 2 π

sin^{2} (x) - cos^{2} (x) + cos (x) = 0, 0 \leq x \leq 2 π

\frac{1}{cos ( 2 x )} + tan (2 x) = 3 cos (2 x)

tan (θ) = - 24

What is the general solution for (sin(θ)-1)(sin(θ)+1)=0 ?
The general solution for (sin(θ)-1)(sin(θ)+1)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin