What is the general solution for sin(x)+cos(x)=0,-pi/2 <= x<= pi ?

The general solution for sin(x)+cos(x)=0,-pi/2 <= x<= pi is x=(3pi)/4 ,x=-pi/4

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sin(x)+cos(x)=0,-pi/2 <= x<= pi

sin (x) + cos (x) = 0, - \frac{π}{2} \leq x \leq π

x = \frac{3 π}{4}, x = - \frac{π}{4}

Solution steps

sin (x) + cos (x) = 0, - \frac{π}{2} \leq x \leq π

Rewrite using trig identities

tan (x) + 1 = 0

Move

1

to the right side

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

Solutions for the range

- \frac{π}{2} \leq x \leq π

x = \frac{3 π}{4}, x = - \frac{π}{4}

sin (x) = \frac{7}{4}

2 tan^{2} (x) + 9 tan (x) + 3 = 0

sin^{2} (x) = (\frac{2 m - 4}{5})

1.25 cos^{2} (θ) + 0.694 cos (θ) - 0.519 = 0

sec (θ) = \frac{13}{12}

What is the general solution for sin(x)+cos(x)=0,-pi/2 <= x<= pi ?
The general solution for sin(x)+cos(x)=0,-pi/2 <= x<= pi is x=(3pi)/4 ,x=-pi/4