What is the general solution for cos(θ)= 1/(sqrt(6)) ?

The general solution for cos(θ)= 1/(sqrt(6)) is θ=1.15026…+2pin,θ=2pi-1.15026…+2pin

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cos(θ)= 1/(sqrt(6))

cos (θ) = \frac{1}{6}

θ = 1.15026 \dots + 2 πn, θ = 2 π - 1.15026 \dots + 2 πn

Solution steps

cos (θ) = \frac{1}{6}

Simplify

\frac{1}{6} : \frac{6}{6}

Apply trig inverse properties

θ = arccos (\frac{6}{6}) + 2 πn, θ = 2 π - arccos (\frac{6}{6}) + 2 πn

Show solutions in decimal form

θ = 1.15026 \dots + 2 πn, θ = 2 π - 1.15026 \dots + 2 πn

sin (x) - 3 cos (x) = 2

(sin (x) - 1) (sin (x) - 3) = 0

x, sin (x) + y^{2} = 4

4 tan^{2} (θ) = - 3 tan (θ) + tan^{2} (θ)

2 sec^{2} (x) - 3 tan (x) = 11

What is the general solution for cos(θ)= 1/(sqrt(6)) ?
The general solution for cos(θ)= 1/(sqrt(6)) is θ=1.15026…+2pin,θ=2pi-1.15026…+2pin