What is the general solution for 8tan(θ)+9=0 ?

The general solution for 8tan(θ)+9=0 is θ=-0.84415…+pin

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8tan(θ)+9=0

8 tan (θ) + 9 = 0

θ = - 0.84415 \dots + πn

Solution steps

8 tan (θ) + 9 = 0

Move

9

to the right side

8 tan (θ) = - 9

Divide both sides by

8

tan (θ) = - \frac{9}{8}

Apply trig inverse properties

θ = arctan (- \frac{9}{8}) + πn

Show solutions in decimal form

θ = - 0.84415 \dots + πn

1 + tanh^{2} (x) = sech^{2} (x)

cos (x) - sin (x) = \frac{1}{2}

tan (t) = - \frac{12}{5}

2 cos (x) - 2 sin (x) cos (x) = 0

3 cot (θ) + 1 = 0, 0 \leq θ \leq 2 π

What is the general solution for 8tan(θ)+9=0 ?
The general solution for 8tan(θ)+9=0 is θ=-0.84415…+pin