What is the general solution for sin(4(x-pi/4))=0 ?

The general solution for sin(4(x-pi/4))=0 is x=(pin)/2+pi/4 ,x=(pi+pin)/2

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sin(4(x-pi/4))=0

sin (4 (x - \frac{π}{4})) = 0

x = \frac{πn}{2} + \frac{π}{4}, x = \frac{π + πn}{2}

Solution steps

sin (4 (x - \frac{π}{4})) = 0

General solutions for

sin (4 (x - \frac{π}{4})) = 0

4 (x - \frac{π}{4}) = 0 + 2 πn, 4 (x - \frac{π}{4}) = π + 2 πn

Solve

4 (x - \frac{π}{4}) = 0 + 2 πn : x = \frac{πn}{2} + \frac{π}{4}

Solve

4 (x - \frac{π}{4}) = π + 2 πn : x = \frac{π + πn}{2}

x = \frac{πn}{2} + \frac{π}{4}, x = \frac{π + πn}{2}

3 arcsin (2 θ) = 2 π

cos^{3} (x) + cos^{2} (x) - cos (x) - 1 = 0

tan (2 θ) = 1, 0^{\circ} \leq θ \leq 36 0^{\circ}

2 cos (θ) + 2 = 0, 0 \leq θ \leq 2 π

3 tan (\frac{θ}{2}) - 1 = 0

What is the general solution for sin(4(x-pi/4))=0 ?
The general solution for sin(4(x-pi/4))=0 is x=(pin)/2+pi/4 ,x=(pi+pin)/2