What is the general solution for 2csc(θ)+2=0 ?

The general solution for 2csc(θ)+2=0 is θ=(3pi)/2+2pin

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2csc(θ)+2=0

2 csc (θ) + 2 = 0

θ = \frac{3 π}{2} + 2 πn

Solution steps

2 csc (θ) + 2 = 0

Move

2

to the right side

2 csc (θ) = - 2

Divide both sides by

2

csc (θ) = - 1

General solutions for

csc (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

cos (x + 2 π) = 1 - cos (x - 2 π)

sin^{4} (\frac{x}{3}) + cos^{4} (\frac{x}{3}) = \frac{5}{8}

arctan (x) = \frac{85}{( \frac{150}{2} - ( \frac{65}{4} ) )}

4 cos^{2} (2 x) = 3

- 2 sin (x) = 1

What is the general solution for 2csc(θ)+2=0 ?
The general solution for 2csc(θ)+2=0 is θ=(3pi)/2+2pin