What is the general solution for sin(2x)cot(x)=0 ?

The general solution for sin(2x)cot(x)=0 is x= pi/2+pin

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sin(2x)cot(x)=0

sin (2 x) cot (x) = 0

x = \frac{π}{2} + πn

Solution steps

sin (2 x) cot (x) = 0

Solving each part separately

sin (2 x) = 0 or cot (x) = 0

sin (2 x) = 0 : x = πn, x = \frac{π}{2} + πn

cot (x) = 0 : x = \frac{π}{2} + πn

Combine all the solutions

x = πn, x = \frac{π}{2} + πn

Since the equation is undefined for:

πn

x = \frac{π}{2} + πn

3 sec (θ) - 23 = 0

sin^{2} (θ) cos (θ) = cos (θ)

cos (3 0^{\circ} + x) = 276

3 sin (2 x) + cos (2 x) = 2 cos (2 x)

sin (x) = - sin (x) cos (x)

What is the general solution for sin(2x)cot(x)=0 ?
The general solution for sin(2x)cot(x)=0 is x= pi/2+pin