What is the general solution for sin(t)cos(t)=sin^2(t) ?

The general solution for sin(t)cos(t)=sin^2(t) is t=2pin,t=pi+2pin,t= pi/4+pin

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sin(t)cos(t)=sin^2(t)

sin (t) cos (t) = sin^{2} (t)

t = 2 πn, t = π + 2 πn, t = \frac{π}{4} + πn

Solution steps

sin (t) cos (t) = sin^{2} (t)

Subtract

sin^{2} (t)

from both sides

sin (t) cos (t) - sin^{2} (t) = 0

Factor

sin (t) cos (t) - sin^{2} (t) : sin (t) (cos (t) - sin (t))

sin (t) (cos (t) - sin (t)) = 0

Solving each part separately

sin (t) = 0 or cos (t) - sin (t) = 0

sin (t) = 0 : t = 2 πn, t = π + 2 πn

cos (t) - sin (t) = 0 : t = \frac{π}{4} + πn

Combine all the solutions

t = 2 πn, t = π + 2 πn, t = \frac{π}{4} + πn

cos (x) = \frac{290}{346.7}

tan (x) = \frac{19}{11}

cot (x) = cot (3 x - 5 0^{\circ}), 0 < x < 18 0^{\circ}

tan (2 θ) = \frac{4}{3}

3 sec^{2} (x) + 2 - 8 tan (x) = 0

What is the general solution for sin(t)cos(t)=sin^2(t) ?
The general solution for sin(t)cos(t)=sin^2(t) is t=2pin,t=pi+2pin,t= pi/4+pin