What is the general solution for 3cos^2(x)-6cos(x)=-3,0<= x<= 2pi ?

The general solution for 3cos^2(x)-6cos(x)=-3,0<= x<= 2pi is x=0,x=2pi

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3cos^2(x)-6cos(x)=-3,0<= x<= 2pi

3 cos^{2} (x) - 6 cos (x) = - 3, 0 \leq x \leq 2 π

x = 0, x = 2 π

Solution steps

3 cos^{2} (x) - 6 cos (x) = - 3, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = 1

cos (x) = 1, 0 \leq x \leq 2 π : x = 0, x = 2 π

Combine all the solutions

x = 0, x = 2 π

csc (θ) + 2 = 0, 0 \leq θ \leq 2 π

sin^{2} (x) + 5 sin (x) - 3 = 0

2 - 3 sin (θ + \frac{4 π}{3}) = 2

tan (θ) = \frac{2}{6}

4 + 3 cos (x) = 0

What is the general solution for 3cos^2(x)-6cos(x)=-3,0<= x<= 2pi ?
The general solution for 3cos^2(x)-6cos(x)=-3,0<= x<= 2pi is x=0,x=2pi