What is the general solution for arcsin(3/5)+arccos(x)=pi ?

The general solution for arcsin(3/5)+arccos(x)=pi is x=-4/5

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arcsin(3/5)+arccos(x)=pi

arcsin (\frac{3}{5}) + arccos (x) = π

x = - \frac{4}{5}

Solution steps

arcsin (\frac{3}{5}) + arccos (x) = π

Move

arcsin (\frac{3}{5})

to the right side

arccos (x) = π - arcsin (\frac{3}{5})

Apply trig inverse properties

x = - \frac{4}{5}

cos (θ) = \frac{6}{7}

2 cos (2 θ) + 7 sin (θ) = 5

tan (x^{2}) = 1

cos (x) = \frac{5}{10}

cos^{2} (x) + 9 cos (x) + 18 = 0

What is the general solution for arcsin(3/5)+arccos(x)=pi ?
The general solution for arcsin(3/5)+arccos(x)=pi is x=-4/5