What is the general solution for 1-sin(θ)=sin(θ) ?

The general solution for 1-sin(θ)=sin(θ) is θ= pi/6+2pin,θ=(5pi)/6+2pin

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1-sin(θ)=sin(θ)

1 - sin (θ) = sin (θ)

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

1 - sin (θ) = sin (θ)

Solve by substitution

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2} : θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Combine all the solutions

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

cot (\frac{θ}{3} + \frac{3 π}{4}) = 3

cos (x) = \frac{tan ( x ) + cot ( x )}{csc ( x )}

- tan^{2} (x) - 1 = 0

2 cot^{2} (y) + 3 csc (y) = 0

cot (x) = - 0.456

What is the general solution for 1-sin(θ)=sin(θ) ?
The general solution for 1-sin(θ)=sin(θ) is θ= pi/6+2pin,θ=(5pi)/6+2pin