What is the general solution for sin(θ)tan(θ)-sin(θ)=0 ?

The general solution for sin(θ)tan(θ)-sin(θ)=0 is θ=2pin,θ=pi+2pin,θ= pi/4+pin

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sin(θ)tan(θ)-sin(θ)=0

sin (θ) tan (θ) - sin (θ) = 0

θ = 2 πn, θ = π + 2 πn, θ = \frac{π}{4} + πn

Solution steps

sin (θ) tan (θ) - sin (θ) = 0

Factor

sin (θ) tan (θ) - sin (θ) : sin (θ) (tan (θ) - 1)

sin (θ) (tan (θ) - 1) = 0

Solving each part separately

sin (θ) = 0 or tan (θ) - 1 = 0

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

tan (θ) - 1 = 0 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn, θ = \frac{π}{4} + πn

6 cos^{2} (x) + 5 sin (x) = 7

sin (θ) = 0.9848, 0^{\circ} \leq θ < 36 0^{\circ}

sin^{2} (x) = \frac{( 7 m - 9 )}{9}

sin (x) = 2, 0 < x < 2 π

2 csc^{2} (x) - 2 csc (x) - 1 = 0

What is the general solution for sin(θ)tan(θ)-sin(θ)=0 ?
The general solution for sin(θ)tan(θ)-sin(θ)=0 is θ=2pin,θ=pi+2pin,θ= pi/4+pin