What is the general solution for 64cosh^4(x)-64cosh^2(x)-9=0 ?

The general solution for 64cosh^4(x)-64cosh^2(x)-9=0 is x= 1/2 ln(2),x=-1/2 ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

64cosh^4(x)-64cosh^2(x)-9=0

64 cosh^{4} (x) - 64 cosh^{2} (x) - 9 = 0

x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

Solution steps

64 cosh^{4} (x) - 64 cosh^{2} (x) - 9 = 0

Rewrite using trig identities

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0

64 (\frac{e ^{x} + e ^{- x}}{2})^{4} - 64 (\frac{e ^{x} + e ^{- x}}{2})^{2} - 9 = 0 : x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

x = \frac{1}{2} ln (2), x = - \frac{1}{2} ln (2)

1 + cos (θ) = 1

tan (2 θ) = 0.4

csc (\frac{θ}{2}) = sin (\frac{θ}{2})

sin (3 x) = - 1, 0 \leq x \leq 2 π

sin (θ) = 0.25

What is the general solution for 64cosh^4(x)-64cosh^2(x)-9=0 ?
The general solution for 64cosh^4(x)-64cosh^2(x)-9=0 is x= 1/2 ln(2),x=-1/2 ln(2)