What is the general solution for -4cos^2(x)+6cos(x)=2 ?

The general solution for -4cos^2(x)+6cos(x)=2 is x= pi/3+2pin,x=(5pi)/3+2pin,x=2pin

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-4cos^2(x)+6cos(x)=2

- 4 cos^{2} (x) + 6 cos (x) = 2

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = 2 πn

Solution steps

- 4 cos^{2} (x) + 6 cos (x) = 2

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = 1

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = 2 πn

sec (θ) = - \frac{4}{3}

tan (2 x) = tan (201 8^{\circ})

- sin (x) + 2 cos^{2} (x) = 1

\frac{6}{π} - 4 sin (2 x) = 0

sin (t) = \frac{1}{5}

What is the general solution for -4cos^2(x)+6cos(x)=2 ?
The general solution for -4cos^2(x)+6cos(x)=2 is x= pi/3+2pin,x=(5pi)/3+2pin,x=2pin