Is 1/(sec(x)-tan(x))=sec(x)+tan(x) ?

The answer to whether 1/(sec(x)-tan(x))=sec(x)+tan(x) is True

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prove 1/(sec(x)-tan(x))=sec(x)+tan(x)

prove

\frac{1}{sec ( x ) - tan ( x )} = sec (x) + tan (x)

True

Solution steps

\frac{1}{sec ( x ) - tan ( x )} = sec (x) + tan (x)

Manipulating left side

\frac{1}{sec ( x ) - tan ( x )}

Rewrite using trig identities

= sec (x) + tan (x)

We showed that the two sides could take the same form

\Rightarrow True

cos (9 0^{\circ})

cos (- \frac{3 π}{4})

sin (- \frac{5 π}{6})

sin (3 7^{\circ})

sin (2 x) = 1

Is 1/(sec(x)-tan(x))=sec(x)+tan(x) ?
The answer to whether 1/(sec(x)-tan(x))=sec(x)+tan(x) is True