What is the general solution for 2tan^2(θ)-2=0 ?

The general solution for 2tan^2(θ)-2=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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2tan^2(θ)-2=0

2 tan^{2} (θ) - 2 = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

2 tan^{2} (θ) - 2 = 0

Solve by substitution

tan (θ) = 1, tan (θ) = - 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

sin^{2} (x) = 2 - sin (x)

2 csc (x) cos (x) = csc (x)

2 cot^{2} (2 x) = 6

- 3 sin (y) = 0

cos (x) = \frac{4}{9}

What is the general solution for 2tan^2(θ)-2=0 ?
The general solution for 2tan^2(θ)-2=0 is θ= pi/4+pin,θ=(3pi)/4+pin