What is the general solution for 100=100+30sin((12pi)/5 t) ?

The general solution for 100=100+30sin((12pi)/5 t) is t=(5n)/6 ,t= 5/12+(5n)/6

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100=100+30sin((12pi)/5 t)

100 = 100 + 30 sin (\frac{12 π}{5} t)

t = \frac{5 n}{6}, t = \frac{5}{12} + \frac{5 n}{6}

Solution steps

100 = 100 + 30 sin (\frac{12 π}{5} t)

Switch sides

100 + 30 sin (\frac{12 π}{5} t) = 100

Subtract

100

from both sides

100 + 30 sin (\frac{12 π}{5} t) - 100 = 100 - 100

Simplify

30 sin (\frac{12 π}{5} t) = 0

Divide both sides by

30

sin (\frac{12 π}{5} t) = 0

General solutions for

sin (\frac{12 π}{5} t) = 0

\frac{12 π}{5} t = 0 + 2 πn, \frac{12 π}{5} t = π + 2 πn

Solve

\frac{12 π}{5} t = 0 + 2 πn : t = \frac{5 n}{6}

Solve

\frac{12 π}{5} t = π + 2 πn : t = \frac{5}{12} + \frac{5 n}{6}

t = \frac{5 n}{6}, t = \frac{5}{12} + \frac{5 n}{6}

\frac{10}{sin ( x )} = \frac{100}{sin ( 9 0 ^{\circ} )}

\frac{sin ( 12 0 ^{\circ} )}{2.34} = \frac{sin ( θ )}{1.2}

tan (x) = \frac{12}{50}

sin (x) - 2 sin (x) \cdot cos (x) = 0

(cos (x) - 1) (cos (x) + 1) = 0

What is the general solution for 100=100+30sin((12pi)/5 t) ?
The general solution for 100=100+30sin((12pi)/5 t) is t=(5n)/6 ,t= 5/12+(5n)/6