What is the general solution for (2cos(x)-1)(sin(x)-1)=0 ?

The general solution for (2cos(x)-1)(sin(x)-1)=0 is x= pi/3+2pin,x=(5pi)/3+2pin,x= pi/2+2pin

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(2cos(x)-1)(sin(x)-1)=0

(2 cos (x) - 1) (sin (x) - 1) = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = \frac{π}{2} + 2 πn

Solution steps

(2 cos (x) - 1) (sin (x) - 1) = 0

Solving each part separately

2 cos (x) - 1 = 0 or sin (x) - 1 = 0

2 cos (x) - 1 = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = \frac{π}{2} + 2 πn

cos (3 2^{\circ}) = sin (5 m) - 12

3 = 2 - 2 sin (θ)

sin (θ) = \frac{563}{2000}

6 sec (2 x) - 8 = 0

0 = cos (x) + cos (2 x)

What is the general solution for (2cos(x)-1)(sin(x)-1)=0 ?
The general solution for (2cos(x)-1)(sin(x)-1)=0 is x= pi/3+2pin,x=(5pi)/3+2pin,x= pi/2+2pin