What is the general solution for sin((3(pi-x))/2)=0 ?

The general solution for sin((3(pi-x))/2)=0 is x=-(4pin)/3+pi,x=-(2pi+4pin)/3+pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin((3(pi-x))/2)=0

sin (\frac{3 ( π - x )}{2}) = 0

x = - \frac{4 πn}{3} + π, x = - \frac{2 π + 4 πn}{3} + π

Solution steps

sin (\frac{3 ( π - x )}{2}) = 0

General solutions for

sin (\frac{3 ( π - x )}{2}) = 0

\frac{3 ( π - x )}{2} = 0 + 2 πn, \frac{3 ( π - x )}{2} = π + 2 πn

Solve

\frac{3 ( π - x )}{2} = 0 + 2 πn : x = - \frac{4 πn}{3} + π

Solve

\frac{3 ( π - x )}{2} = π + 2 πn : x = - \frac{2 π + 4 πn}{3} + π

x = - \frac{4 πn}{3} + π, x = - \frac{2 π + 4 πn}{3} + π

sin (x) (2 - sin (x)) = cos^{2} (x)

sin^{2} (θ) = \frac{7}{9}

1 - tan^{2} (θ) = 0

3 - tan (3 θ) = 0

3 cot (3 x) - 3 = 0

What is the general solution for sin((3(pi-x))/2)=0 ?
The general solution for sin((3(pi-x))/2)=0 is x=-(4pin)/3+pi,x=-(2pi+4pin)/3+pi