What is the general solution for 8cos(B)+sqrt(52)=8 ?

The general solution for 8cos(B)+sqrt(52)=8 is B=1.47202…+2pin,B=2pi-1.47202…+2pin

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8cos(B)+sqrt(52)=8

8 cos (B) + 52 = 8

B = 1.47202 \dots + 2 πn, B = 2 π - 1.47202 \dots + 2 πn

Solution steps

8 cos (B) + 52 = 8

52 = 213

8 cos (B) + 213 = 8

Move

213

to the right side

8 cos (B) = 8 - 213

Divide both sides by

8

cos (B) = \frac{4 - 13}{4}

Apply trig inverse properties

B = arccos (\frac{4 - 13}{4}) + 2 πn, B = 2 π - arccos (\frac{4 - 13}{4}) + 2 πn

Show solutions in decimal form

B = 1.47202 \dots + 2 πn, B = 2 π - 1.47202 \dots + 2 πn

sin (a x) = 0

cos (x + 3 0^{\circ}) = 2 cos (x)

x, sec (x) tan (x) = 23

4 sin (θ) - 4 cos (θ) = 2

4 sin (x) + 22 = 0

What is the general solution for 8cos(B)+sqrt(52)=8 ?
The general solution for 8cos(B)+sqrt(52)=8 is B=1.47202…+2pin,B=2pi-1.47202…+2pin