What is the general solution for sin(θ)= 4/5 ,cos(θ) ?

The general solution for sin(θ)= 4/5 ,cos(θ) is No Solution for θ\in\mathbb{R}

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sin(θ)= 4/5 ,cos(θ)

sin (θ) = \frac{4}{5}, cos (θ)

No Solution for θ \in R

Solution steps

sin (θ) = \frac{4}{5}, cos (θ)

Apply trig inverse properties

sin (θ) = \frac{4}{5}

General solutions for

sin (θ) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

cos (θ)

No Solution for θ \in R

sin (6 x) = cos (3 x)

sin (\frac{θ}{2}) - cos (\frac{θ}{2}) = 0

sin (x) = \frac{- 3}{5}

3 cos^{2} (a) + sin^{2} (a) = 2

2 cos (6 x) + 3 = 0

What is the general solution for sin(θ)= 4/5 ,cos(θ) ?
The general solution for sin(θ)= 4/5 ,cos(θ) is No Solution for θ\in\mathbb{R}