What is the general solution for 2=2sin(3θ) ?

The general solution for 2=2sin(3θ) is θ= pi/6+(2pin)/3

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2=2sin(3θ)

2 = 2 sin (3 θ)

θ = \frac{π}{6} + \frac{2 πn}{3}

Solution steps

2 = 2 sin (3 θ)

Switch sides

2 sin (3 θ) = 2

Divide both sides by

2

sin (3 θ) = 1

General solutions for

sin (3 θ) = 1

3 θ = \frac{π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}

sin (\frac{π}{3} - x) = \frac{1}{2}

sin (x) = \frac{2}{3}

0.1 cos (x) + 0.45 sin (x) = 0.3125

2 sin (2 x) cos (3 x) + cos (3 x) = 0

cos^{2} (x) - 3 sin^{2} (x) = - 2

What is the general solution for 2=2sin(3θ) ?
The general solution for 2=2sin(3θ) is θ= pi/6+(2pin)/3