What is the general solution for sin(3θ)=-(sqrt(2))/2 ?

The general solution for sin(3θ)=-(sqrt(2))/2 is θ=(5pi}{12}+(2pin)/3 ,θ=(7pi)/(12)+\frac{2pin)/3

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sin(3θ)=-(sqrt(2))/2

sin (3 θ) = - \frac{2}{2}

θ = \frac{5 π}{12} + \frac{2 πn}{3}, θ = \frac{7 π}{12} + \frac{2 πn}{3}

Solution steps

sin (3 θ) = - \frac{2}{2}

General solutions for

sin (3 θ) = - \frac{2}{2}

3 θ = \frac{5 π}{4} + 2 πn, 3 θ = \frac{7 π}{4} + 2 πn

Solve

3 θ = \frac{5 π}{4} + 2 πn : θ = \frac{5 π}{12} + \frac{2 πn}{3}

Solve

3 θ = \frac{7 π}{4} + 2 πn : θ = \frac{7 π}{12} + \frac{2 πn}{3}

θ = \frac{5 π}{12} + \frac{2 πn}{3}, θ = \frac{7 π}{12} + \frac{2 πn}{3}

sin (x) - 3 cos (x) = 2

3 tan (15 x^{5}) + 1 = 0

4 cos (θ) - 3 sec (θ) = 0

sin (x) = \frac{π}{6}

(2 sin (4 x) - 1) \cdot (1 + tan (x)) = 0

What is the general solution for sin(3θ)=-(sqrt(2))/2 ?
The general solution for sin(3θ)=-(sqrt(2))/2 is θ=(5pi}{12}+(2pin)/3 ,θ=(7pi)/(12)+\frac{2pin)/3