What is the general solution for -2=2sqrt(2)cos(θ) ?

The general solution for -2=2sqrt(2)cos(θ) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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-2=2sqrt(2)cos(θ)

- 2 = 22 cos (θ)

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

- 2 = 22 cos (θ)

Switch sides

22 cos (θ) = - 2

Divide both sides by

22

cos (θ) = - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

cos^{2} (2 x) = 1

- 4 cos^{2} (θ) = - 1

- sin (2 x) + sin (x) = 0

sin^{2} (x) = 3 (1 - cos (x))

cos (x) = \frac{1}{10}

What is the general solution for -2=2sqrt(2)cos(θ) ?
The general solution for -2=2sqrt(2)cos(θ) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin