What is the general solution for sin^2(x)-cos(x)tan(x)=0 ?

The general solution for sin^2(x)-cos(x)tan(x)=0 is x=2pin,x=pi+2pin

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sin^2(x)-cos(x)tan(x)=0

sin^{2} (x) - cos (x) tan (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

sin^{2} (x) - cos (x) tan (x) = 0

Rewrite using trig identities

- sin (x) + sin^{2} (x) = 0

Solve by substitution

sin (x) = 1, sin (x) = 0

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

x = 2 πn, x = π + 2 πn

sin (x + 3 0^{\circ}) = \frac{1}{2}

sin (θ) = 21

0 = - 2 sin (2 x) + cos (2 x)

y, arcsin (y) = arcsin (x)

4 csc (x) + 2 sin (x) = 9

What is the general solution for sin^2(x)-cos(x)tan(x)=0 ?
The general solution for sin^2(x)-cos(x)tan(x)=0 is x=2pin,x=pi+2pin